Problem 63-6    Source: Problem elaborated by the author of the site.

A tap-central full wave rectifier has a rectified voltage of V_Cmax = 35  V. The ripple factor is r = 3%. Which is value of the maximum load that the rectifier supports if we have C = 2,200 µF ? (consider f = 60 Hz).

Solution of the Problema 63-6   

Note that this problem gives the ripple value in rms value. So to find the load that can be used, we must use the eq. 63-16a, reproduced below.

By substituting numerical values, we find: