Problem 71-1    Source:  Example 26-8 - page 810 - KNIGHT, Randall D. -    Book: Física - Uma Abordagem Estratégica - 2ª Edição - Ed. Bookman - 2009.

In a hydrogen atom, the electron describes an orbit with a radius of 0.053 nm around the proton.

a) What is the intensity of the electric field created by the proton at the position of the electron?.

b) What is the magnitude of the electrical force exerted on the electron?

Solution of the Problem 71-1   

Item a   

We must remember that the charge of the proton is equal to the charge of the electron, that is, q = 1.6 x 10^-19C. So, we can determine the intensity of the electric field at the place where the electron is located, knowing that r = 0.053 nm = 5.3 x 10 ^-11m and using the eq. 71-05 . This way we have

Performing the calculation we find the module of the intensity of the electric field, or

Item b   

As we know the electric field and the charge of the electron, to find the electrical force to which the electron is subjected we can use the eq. 71-02.