Problem 45-3 Source:
Problem 5.39 - page 120 - NILSSON & RIEDEL -
Book: Circuitos Elétricos - 8ª edição - Ed. Pearson Education do Brasil - 2010.
In the circuit show in Figure 45-03.1, the resistor Rx is set so that the ideal operational amplifier is exactly at the point of saturation. Determine the value of Rx in kΩ.
Solution of the Problem 45-3
Initially, one must investigate whether the voltage at the output will be positive or
negative.
With this, it must be determined whether the output voltage at saturation will be 20 volts (if it is positive) or equal to - 10 volts (negative case). We know (by the circuit) that the voltage at the input is negative and equal to - 4 volts. When amplified by the inverter input of the operational amplifier, a positive voltage is generated in the output. Therefore, it is concluded that
Vo = 20 volts.
Using a voltage divider to calculate the value of Vb and remembering that
Vi = -4 volts, we obtain:
It is also known that, virtually, Va = Vb = -0.8 volt.
As we know the value of the input voltage, then we can calculate the current that flows through of the
resistance of 2 kΩ. Then:
Now, this current is the same that flows through of the Rx.Thus we can calculate the value of this resistance because: