Problem 45-2
Source: Problem 4-34 - page 213 - THOMAS, Roland E. ,
ROSA, Albert J. , THOUSSAINT, Gregory J. - Book: The Analysis & Design of Linear Circuits
- 6ª Edição - Ed. John Willey & Sons, Inc. - 2009.
Use the nodal analysis method to show that in the circuit of the Figure 45-02.1io = - Vs / 2 R , independent of the load RL.
In other words, show that the circuit of the figure below is a current source
voltage controlled (Vs).
Solution of the Problem 45-2
Using the ideal model of an operational amplifier, it is known that no electric current circulates in the inputs of the amplifier.
Then, based on the figure above, we can write to the left side of the circuit the equation:
(Vs - Va ) / 2 R = (Va - Vo ) / R
Working algebraically this equation and rewriting it:
Vo = (3 / 2) Va - (1 / 2) Vs
eq. 45-02.1
On the other hand, on the right side of the circuit RL is in parallel with 2 R.
The result of this parallel is shown in the equation below:
Req = 2 R RL / (2 R + RL )
Using this result, the equation for the right side of the circuit results.
(Vo - Vb) / R = Vb / Req
Not forgetting that for an ideal operational amplifier, we have
Va = Vb.Thus, taking this into consideration and
replacing in the previous equation, Req
by the value of the parallel and by simplifying similar terms, we obtain:
Vo = (3 /2) Va + Va (R / RL)
eq. 45-02.2
Note that, the equations eq. 45-02.1 and eq. 45-02.2 above, express
Vo in function of
Va e Vs. Then, equating these equations:
(3 /2) Va - (1 / 2) Vs = (3 /2) Va + Va (R / RL )
We can cancel the terms (3/2) Va. So expressing
Va in function of Vs:
Va = - (RL / 2 R) Vs
In possession of the value of Va, and remembering again that
Va = Vb, we can write iL as:
iL = Va / RL
Replacing the value of Va nthis equation and carrying out the appropriate simplifications, the desired result is achieved, or:
iL = - Vs / 2 R
Therefore, it is clear that the value of iL is totally
independent of the value of RL. In this way, iL
depends only on the input voltage Vs and the value of
resistor R. Thus, with the choice of these values there is how to design a source of constant current controlled by voltage with the desired value,
provided that the limitations of the operational amplifier used in the design are obeyed.