Problem 2.6   Source:   Problem elaborated by the author of the site.

In the circuit shown in Figure 02-06.1 find the equivalent resistance seen from the terminals a-b.

Solution of the Problem 2.6

Note that resistors of values of 8 Ω and 7 Ω are in series, resulting in a resistor of 8 + 7 = 15 Ω. And this resistor is in parallel with the resistor of 10 ohms. Resolving this parallel we find as a result the value of 6 Ω which is the resistance value between points 1 - 2. Thus, we realize that we have three resistors in series. So the equivalent resistance between the points a -b is: