Problem 44-1
Source: Problem 4-26 - page 211 - THOMAS, Roland E. ,
ROSA, Albert J. , THOUSSAINT, Gregory J. - Book: The Analysis & Design of Linear Circuits
- 6ª Edição - Ed. John Willey & Sons, Inc. - 2009.
a) Find Vo in terms of the inputs V1
and V2 of the circuit in the Figure 44-01.1.
b) If V1 = 1 V what is the range of values V2 can have without saturing the Opamp?
Figure 44-01.1
Solution of the Problem 44-1
Item a
The output voltage of an addition amplifier is given by the eq. 44-01
shown in below.
eq. 44-01
Comparing the equation with the circuit we easily conclude that:
Rf = 300 kΩ , R1 = 100 kΩ e
R2 = 150 kΩ
Also, taking into account that by the equation, Va = V1 and
Vb = V2, we can write the equation that determines the voltage of
circuit output, that is:
Vo= - 3 V1 - 2 V2
Item b
It is understood by saturation of the output of an operational amplifier the value of the voltage of limit input where the output assumes the maximum value the value of the supply voltage of the circuit. From this value, increasing even more
the input voltage, there will be no proportional increase in the output voltage. Therefore,
if Vcc = ± 15 V the maximum output voltage will be ± 15 V.
This item of the problem admits two solutions: one is when the output reaches the limit voltage of
- 15 volts; other, it is when the output voltage reaches the limit value of + 15 volts.
1ª Solution
In this way, if V1 = 1 V, and supposing V2 = 0, we get
in the output a voltage of:
Vo= - 3 x 1 = - 3 volts
So to reach the voltage of - 15 volts, which is the maximum voltage that the output can take, a contribution must be made by V2 of:
Vo= - 3 x 1 - 2 x 6 = - 15 volts
Therefore, making V2 ≤ 6 volts the objective of the
problem is reached.
2ª Solution
Note that in the previous solution a positive voltage was used to V2.
However, it is possible to place a negative voltage on V2.
Therefore, its value will be:
Vo= - 3 x 1 - 2 (-9) = + 15 volts
Therefore, the other value that V2 can assume is V2 ≥ - 9 volts.
Attention
In order to obtain the complete solution of the problem, one must join the two solutions found. So, the correct answer is: