Problem 13-6 Source:
Adapted from Exercise 3.7 - page 87 - ALEXANDER, Charles K. &
SADIKU, Matthew N. O. - Book: Fundamentos de Circutos Elétricos - 5ª edição - Ed. McGrawHill - 2013.
For the circuit shown in the Figure 13-06.1, determine the currents in the circuit and the current value
Io, as well as the power received and / or supplied by the source 10 V.
Solution of the Problem 13-6 -
Kirchhoff Method
In this problem it should be noted that the meshes traveled by I1 and
I2 have in common a source of current of 5A . As we saw
in item 3, this characterizes a super-mesh
(to review: Super-mesh Concept). In the same way,
we have another super-mesh in relation to
I2 and I3. As the two super-mesh intercept, as represented by the dotted
line in green, in the figure above, one can write the equation for this super-mesh as follows:
2 I1 + 4 I2 + 8 (I3 - I4) + 6 I2 = 0
Working algebraically with this equation and simplifying, one obtains:
I1 + 3 I2 + 6 I3 - 4 I4 = 0
In addition, for the node a we have the following relation:
I2 = I1 + 5
And for the e node, we can write:
I2 = I3 + 3 Io
But from the circuit, we know thatIo = - I4. Then, the above equation can be written as:
I2 = I3 - 3 I4
And finally we can write the equation for the mesh where I4 circulates, or:
2 I4 + 8 (I4 - I3) = - 10
To simplify this equation, we obtain:
-4 I3 + 5 I4 = - 5
Note that we get the four equations needed to find the four unknowns. This system of equations solved easily using the Octave program. Thus, the currents are:
I1 = -7.5 A
I2 = -2.5 A
I3 = 3.929 A
I4 = 2.143 A
As stated above, Io = - I4, then:
Io = - 2.143 A
To complete the solution of the problem we will calculate the power supplied / received by the source
voltage 10 volts . As the current I4 enters the positive pole of the source, then
it absorbs (receives) circuit power and its value, according to convention, is positive , or: