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    Let the circuit shown in Figure 17-01. We want to calculate the current value i3.

exlinear17-1J.png
Figure 17-01

    Let's start solving the problem by arranging a value for i3. To facilitate calculations, we chose integer values. If i3 = 2 A, then e1 = 30 i3 = 30 x 2 = 60 V. As a consequence, i2 = e1/ 20 = 60 / 20 = 3 A. By the law of knots, we have to i1 = i2 + i3 = 3 + 2 = 5 A . With this result we can calculate the value of V, since V = 8 i1 + e1 = 8 x 5 + 60 = 100 V. Therefore, we obtain the circuit shown in Figure 17-02.

exlinear17-1K.png
Figura 17-02

    Let's interpret our calculations. What we have just calculated means that when we have a voltage source equal to 100 V we obtain a current i3 = 2 A. As we know that the circuit is linear, to know what the value of i3 is when we change the value of the voltage source to 60 V, simply apply a rule of three simple.

exlinear17-1N.png

    Another way is to determine the constant multiplier of the function. So, let's call this constant k and define it as:

    k  =  i3 / V  =  2 / 100  =  1 / 50

    With this data we can write the function that determines the value of i3 as a function of the value of the voltage source, that is:

    i3  =  k   V  =  V / 50

    Logo, nesse exemplo temos:

    i3  =  60 / 50  =  1.2   A

    As you can see, this technique is very simple and effective in solving problems. It can also be used in conjunction with other theorems, such as the superposition theorem. You can compare this result with the one shown in Problem 10-1.