Problem 11-11 Source:
Problem developed by the site author.
In the circuit show in Figure 11-11.1, calculate:
The current I and the electrical voltage at point a, that is,
Va.
Solution of the Problem 11-11 -
Method of Transforming Sources
First of all we must realize that the resistor of 17 ohms can be removed
from the circuit,
because it is between two voltage sources of known values.
On the other hand we have two voltage sources in series with resistors, so we can
apply the principle of source transformation.
In the Figure 11-11.2 we redesigned the circuit with the transformation
applied.
As the two current sources point in opposite directions, we must subtract them.
The resistors of 10 Ω and 2 Ω are in parallel and we can
replace them
by a single of 5/3 Ω , as shown in the Figure 11-11.3.
To calculate the value of I just apply a current divider, that is:
Having the value of I and looking at the original circuit we easily
calculate the value of
Va, or
