Problem 47-7
Source: Adapted from the 2nd question on the list of Elementary Electronics I - Ufrgs - 2019.
For the circuit shown in the Figura 47-07.1, determine the value of N so that the circuit has a predominance of negative feedback. Afterwards, consider the value of N so that the circuit presents a predominance of positive feedback.
Solution of the Problem 47-7
To solve this problem we will use the nodal voltage technique. Remembering that for ideal operational amplifiers, the following list applies:
Va = Vb and V1 = V2
eq. 47-07.1
Now using the nodal method for the point a, we get:
Va / R + (Va - Vx )/ R = 0
After some algebraic manipulation in the equation above, the following relation is obtained:
Vx = 2 Va
eq. 47-07.2
For the point x, we can write:
Vx / 2 R + (Vx - Va ) / R + (Vx - V1 ) / (R/2 ) = 0
Replacing eq. 47-07.2 in the equation above and, after some manipulation algebraic, we get:
V1 = 3 Va
eq. 47-07.3
Now, for the point b, we can write:
(Vb - Vi ) / ( N R ) + (Vb - V2 ) / 2 R = 0
Remembering the equalities in eq. 47-07.1 and substituting it in the equation above, we get:
Vi = (1 - N ) Va
eq. 47-07.4
And finally for point 2, we can write:
(V2 - Vb ) / 2 R + (V2 - Vo ) / R = 0
Again, remembering the equalities in eq. 47-07.1 and substituting it in the equation above, we get:
Vo = 4 Va
eq. 47-07.5
To obtain the circuit gain, just divide eq. 47-07.5 by eq. 47-07.4, that is:
Av = V0 / Vi = 4 / ( 1 - N )
Conclusions
Analyzing the above equation, it is easily concluded that to obtain a negative predominance, we must satisfy the condition below:
N > 1
And to obtain a positive predominance, it is enough to satisfy the condition below:
0 ≤ N < 1
Note that, N cannot take on a value less than zero, as this would imply a passive resistor with a value negative,
which is physically impossible.