Problem 55-19
Source: Example 10.9 - page 396 -
IRWIN, J. David - Book:
Circuit Analysis in Engineering - Ed. Pearson Education do Brasil - 4th edition - 2013.
Determine the voltage Vo in the circuit shown in Figure 55-19.1,
using the Thévenin method.
Solution of the problem by Método Kirchhoffclick here!
Solution of the problem 55-19
- Method of Thévenin
As we know, by Thevenin's theorem it is necessary to determine the Thevenin voltage, Vth,
and the Thevenin impedance, Zth. To apply the method, we must remove from the circuit the
impedance where we want to determine the equivalent circuit. Figure 55-19.2 shows how the
circuit after the necessary modifications.
Looking at the circuit, we easily determine the value of Ix = 4 ∠0°. This data allows
that we directly calculate the value of Vth, making the mesh indicated by the blue arrow
in Figure 55-19.2, or:
Vth = - 4 + j 8 V
Now we must find the equivalent Thévenin impedance, Zth, "viewed" from the points a-b,
as shown in Figure 55-19.3. To do so, we must short circuit the independent voltage source, and remove the
circuit-independent current source. The dependent current source continues in the circuit.
Conveniently, we introduce a current source of 1 A between the a-b terminals.
Note that the arrow on the current source points downwards, so we have Ix = 1 A.
Thus, the dependent current source assumes the value 2 A. Therefore, we conclude that through the inductor must pass
a current of 1 A. So the voltage Vab will be:
Vab = - 1 + j V
Now we can calculate Zth, applying method 3, studied in chapter 15. So:
Zth = Vab / - I = (-1 + j) / -1 = 1 - j Ω
We have the necessary data to design the Thévenin equivalent circuit, as shown in Figure 55-19.4. Soon:
To find the value of Vo let's apply a voltage divider. Then: